x-4/x^2-9*2x+6/3x-12=x

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Solution for x-4/x^2-9*2x+6/3x-12=x equation: 



x-4/x^2-9*2x+6/3x-12=x

We move all terms to the left:

x-4/x^2-9*2x+6/3x-12-(x)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

-4/x^2-9*2x+6/3x-12=0

Wy multiply elements

-4/x^2-18x+6/3x-12=0

We calculate fractions

We do not support expression: x^3

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